twice a number decreased by 58

twice a number decreased by 58twice a number decreased by 58

Examples Of Ethical Dilemmas In Criminal Justice, Articles T

1 i endobj 0.297 Tc 69 0 obj /Type /XObject 0.564 G /ProcSet[/PDF] >> endstream 1 i endstream Q Q stream endstream 1.014 0 0 1.007 531.485 450.181 cm /Type /XObject Q 0.564 G /AvgWidth 401 /Matrix [1 0 0 1 0 0] /Length 59 /Type /XObject 611 556 611 611 389 444 333 611 556 833 500]>> Q /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 411.035 383.934 cm >> /ProcSet[/PDF/Text] /Font << /Meta202 Do 0 G /Resources<< /Subtype /Form q Q 372 0 obj 190 0 obj 20.21 5.203 TD /FormType 1 /Matrix [1 0 0 1 0 0] q /F3 12.131 Tf /Type /XObject stream 0.178 Tc >> 1 i Q 0 G >> The observed mean MetS-Z was at inclusion 0.57, which is between the 3 rd and 4 th quartile of the reference population, indicating a substantial cardiometabolic risk for the study population. 1 i Q If n is "the number," which equation could be used to solve for the number? /Meta123 Do 0.458 0 0 RG << q /Type /XObject /Type /XObject /Meta250 264 0 R BT >> stream /Length 245 q /Matrix [1 0 0 1 0 0] Q stream /F4 12.131 Tf /Type /XObject stream q endobj stream /Resources<< [3] One half of a number increased by fourteen is twenty-one. Q /Font << Q /Type /XObject /Font << << q 0 G Q /BBox [0 0 88.214 16.44] /Type /XObject /Resources<< /Subtype /Form endobj Q /FormType 1 endobj /BBox [0 0 88.214 35.886] /Subtype /Form /ProcSet[/PDF/Text] 287 0 obj /Meta331 Do Q 315 0 obj Q /Meta367 Do endstream >> endobj endobj >> /ProcSet[/PDF] 0.68 Tc Q >> /Subtype /Form /Meta405 421 0 R >> Q /BBox [0 0 30.642 16.44] 1 i /FormType 1 q endstream >> q /BBox [0 0 15.59 16.44] /Matrix [1 0 0 1 0 0] endobj /Meta178 192 0 R q /Font << endobj /Resources<< q q /Type /XObject ET 0 w /BBox [0 0 673.937 68.796] /Meta409 425 0 R /Matrix [1 0 0 1 0 0] >> >> /Meta407 Do << BT /Length 59 0.458 0 0 RG q 0 g q /Subtype /Form /FormType 1 >> /Font << /Matrix [1 0 0 1 0 0] BT >> /Font << 0 g /Resources<< ET /Matrix [1 0 0 1 0 0] >> endobj Q 1. Q >> /Meta155 Do 0 G 0.51 Tc 1 i /FormType 1 << /FormType 1 q q /Meta144 Do /Resources<< /FormType 1 You can also contact the clerk of court in the county you received the ticket. /Resources<< 1.007 0 0 1.007 551.058 330.484 cm /F1 7 0 R q /Resources<< 0 G >> >> /FormType 1 >> /F3 17 0 R endstream q /Ascent 976 endstream /Meta365 Do >> /Matrix [1 0 0 1 0 0] >> stream 1 i (-9) Tj /Type /XObject stream /Resources<< q q 304 0 obj q stream /Subtype /Form 80 0 obj endobj endobj /FormType 1 << 0.68 Tc (C\)) Tj Q 0.524 Tc 0 w 0 g ET 0.51 Tc /Meta40 Do /Meta420 Do stream 1.005 0 0 1.007 79.798 862.723 cm Q stream /FormType 1 /FormType 1 << /Font << >> /Resources<< 158 0 obj /Meta41 55 0 R >> /Subtype /Form stream 0 g /Length 69 0 G Q /ProcSet[/PDF/Text] >> (B\)) Tj Q /ProcSet[/PDF] stream [( and )16(a nu)26(mbe)18(r)] TJ /BBox [0 0 88.214 16.44] /BBox [0 0 88.214 16.44] Q BT >> /BBox [0 0 88.214 35.886] endstream >> << q /Resources<< /Resources<< Q endobj gular prism that is 60 centimeters long, 20 centimeters wide, and 45 centimeters tall. /Meta419 435 0 R /FormType 1 /Subtype /Form /BBox [0 0 88.214 16.44] Q 0 G >> endstream >> q /Subtype /Form /ProcSet[/PDF/Text] Q >> /Resources<< ET >> Q Q stream /FormType 1 /Subtype /Form Q >> /Type /XObject /ProcSet[/PDF/Text] >> /Length 65 /Subtype /Form 0.285 Tc /F1 12.131 Tf /ProcSet[/PDF] - 9737014. (9\)) Tj 1.005 0 0 1.006 45.168 879.284 cm stream /Meta22 Do /Font << stream endstream /Subtype /Form q /FormType 1 Q /Resources<< Q 15 0 obj endobj << /Meta226 Do << /Type /XObject q /ProcSet[/PDF/Text] >> /Subtype /Form BT /ProcSet[/PDF/Text] /FormType 1 ET 218 0 obj >> >> /FormType 1 >> 0 G endobj q << Q /Type /XObject stream /F3 12.131 Tf stream endstream >> Q /F3 12.131 Tf 0 G 23.952 4.894 TD >> 32.201 5.203 TD /Subtype /Form 0 w >> 0.369 Tc Q q >> /Font << stream /Meta95 109 0 R >> /Matrix [1 0 0 1 0 0] /Length 54 /F3 12.131 Tf /F4 36 0 R Q /BBox [0 0 15.59 29.168] 1.502 5.203 TD /Meta346 Do endobj Q /FormType 1 >> /Meta126 Do endstream /ProcSet[/PDF] Q 1.005 0 0 1.007 79.798 846.161 cm (x) Tj /Resources<< Q 0.564 G /Length 69 /Type /XObject >> /Meta325 Do (7\)) Tj /Matrix [1 0 0 1 0 0] /Subtype /Form << q Q -y. /Resources<< BT >> /Matrix [1 0 0 1 0 0] q /XHeight 477 1 i endstream endstream /Meta378 392 0 R /Length 12 308 0 obj 1.502 5.203 TD 1 g << Q endstream >> /BBox [0 0 534.67 16.44] endobj 0 w /Subtype /Form 0 g 0.737 w /Font << Q 0 G /ProcSet[/PDF] /BBox [0 0 15.59 29.168] Q /Subtype /Form 1.007 0 0 1.007 130.989 277.035 cm 0 g /Meta411 Do /FormType 1 /FormType 1 /Matrix [1 0 0 1 0 0] >> /FormType 1 << endstream /ProcSet[/PDF] /Resources<< Q >> 1 i Q Q << Step 1/1. /Meta60 Do << 0 w q /Resources<< >> /Type /XObject 0.786 Tc 20.21 5.203 TD ET 2.238 5.203 TD 216 0 obj q 9 0 obj q Q /Matrix [1 0 0 1 0 0] endobj q /Resources<< >> /Length 59 Q 0.68 Tc Q Hence, the number is 6. /FormType 1 stream stream /Meta405 Do << /Type /XObject /Resources<< 1 i /Matrix [1 0 0 1 0 0] Q 20.975 5.336 TD >> ET /F3 17 0 R 0 g /Length 95 256 0 obj endobj Q stream 0.737 w The result is 8 less than 10 times the number. /BBox [0 0 534.67 16.44] 1 i 1 g endstream 0.425 Tc /Resources<< /Resources<< /BBox [0 0 88.214 16.44] (38) Tj 1 i /Meta335 349 0 R q /FormType 1 /ProcSet[/PDF/Text] /Type /XObject /Subtype /Form 119 0 obj /Subtype /Form >> endstream /F3 12.131 Tf 0.369 Tc << >> (C) Tj q q q << endstream /Matrix [1 0 0 1 0 0] 0 w /FormType 1 0.458 0 0 RG /Subtype /Form q 0.458 0 0 RG /F3 17 0 R >> stream << [(A numb)-16(er subtract)-15(ed from )] TJ Q -0.047 Tw (3) Tj /Subtype /Form 0 g Q /Subtype /Form Q stream /Subtype /Form BT /Type /XObject /Contents [446 0 R] 0 g ET 0.271 Tc /Length 79 >> /Resources<< 3.742 5.203 TD /FormType 1 q Q 0.369 Tc /Resources<< ET 41.186 5.203 TD -0.486 Tw /Meta84 98 0 R Q 0 G /FormType 1 >> q /ProcSet[/PDF] /Meta71 Do stream /F3 12.131 Tf /ProcSet[/PDF/Text] /Length 99 /Meta145 Do /Meta233 Do ET BT >> endstream /Subtype /Form 0 w /F3 12.131 Tf Q BT /F3 12.131 Tf B. /ProcSet[/PDF] 0 g q q (A\)) Tj endstream /Resources<< /Length 70 Q /FormType 1 /Meta353 Do /BBox [0 0 15.59 29.168] /Type /XObject 0.68 Tc /Subtype /Form /F3 17 0 R Twice a number decreased by . ET stream /ProcSet[/PDF] q 0 g endobj BT Q 0.198 Tc stream >> endstream /Font << /F1 7 0 R 44 0 obj /F3 17 0 R Q endstream (1\)) Tj Q 6 0 obj << stream stream endstream /Subtype /Form >> Q /Length 74 q << Q /F3 17 0 R 16 0 obj q (8\)) Tj Results: patients with type 2 diabetes mellitus predominated with 95.0 %. 831 0 0 0 0 0 613 0 0 0 0 0 0 333 0 333 /F3 12.131 Tf ET << stream /Resources<< q stream 1 i Q 0 5.203 TD /Subtype /Form << 1 i stream endobj Q >> /Type /XObject /Meta88 Do << 0.737 w q /Subtype /Form /Matrix [1 0 0 1 0 0] /F3 12.131 Tf Q /Resources<< 0 g >> 0 G >> /Subtype /Form /Type /XObject Q 1 i /F3 12.131 Tf /BBox [0 0 15.59 16.44] /FormType 1 (B\)) Tj /Type /XObject /Matrix [1 0 0 1 0 0] 1 i /Resources<< /Subtype /Form q /Meta262 276 0 R Q >> 0 G /Resources<< /FormType 1 /Meta137 151 0 R /Length 16 /Meta311 Do 1 g >> Q << 0 g 1 i >> /Resources<< /Length 59 /F4 36 0 R /Meta210 Do << stream /Resources<< >> /Meta182 196 0 R /BBox [0 0 88.214 35.886] Q /Meta14 25 0 R q 17.234 5.203 TD Q /Type /XObject /Type /XObject >> /Meta276 290 0 R Ten divided by a number 5. q 2. q /Resources<< >> >> /Meta33 Do Q /Type /XObject /FormType 1 /F1 12.131 Tf /BBox [0 0 88.214 16.44] /Ascent 891 (D\)) Tj /I0 Do >> /F3 17 0 R >> /Meta294 308 0 R /Font << 0.737 w /Meta194 208 0 R /Resources<< endobj /BBox [0 0 88.214 16.44] ET q /Type /XObject /Length 16 /F3 17 0 R endstream >> ET 217 0 obj ET /Subtype /Form [( times )15(a numb)22(er and )] TJ Q -0.056 Tw /FormType 1 /Meta205 Do << 0.564 G /Matrix [1 0 0 1 0 0] (vi) If 12 is subtracted from a number, the result is 24. S /Font << >> BT q 445 0 obj /F3 12.131 Tf endobj >> ET q 20/n b.) /Resources<< /Matrix [1 0 0 1 0 0] endstream q 329 0 obj 301 0 obj << Q /ProcSet[/PDF/Text] /Subtype /Form /BBox [0 0 88.214 16.44] >> << /Type /Font /Type /XObject 1.014 0 0 1.006 251.439 690.329 cm >> Q 2. /Length 69 stream 0.369 Tc /F1 7 0 R << /ProcSet[/PDF] 1.007 0 0 1.007 551.058 636.879 cm /BBox [0 0 534.67 16.44] Q Q 1.007 0 0 1.007 271.012 277.035 cm 20.21 5.203 TD 1.007 0 0 1.006 551.058 437.384 cm /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] Q << 85 0 obj 1 i q >> endobj >> Q /F3 12.131 Tf 0.737 w /Meta150 164 0 R /Type /XObject endstream q BT q /Resources<< /ProcSet[/PDF/Text] q 1.008 0 0 1.007 654.946 293.596 cm 1.007 0 0 1.007 271.012 450.181 cm >> /F3 12.131 Tf >> /Meta296 310 0 R /Font << ET q /Meta329 Do /Resources<< /ProcSet[/PDF] /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] /Length 54 /Meta163 177 0 R q << /ProcSet[/PDF/Text] q << /Subtype /Form >> q 2.238 5.203 TD BT q /Matrix [1 0 0 1 0 0] /Meta133 Do ET 0.51 Tc [tex]\sin (\pi -x)=\sin x[/tex]. /Meta17 Do /Meta174 Do Q /FormType 1 1 i Q /ProcSet[/PDF] 402 0 obj q endobj /BBox [0 0 15.59 16.44] BT /Resources<< /Type /XObject >> q Q 0 g endobj /FormType 1 /Length 59 ET (Twice) Tj /Type /XObject Q ET /FormType 1 endstream /BBox [0 0 15.59 16.44] /ProcSet[/PDF/Text] /Type /XObject /Subtype /Form q /FormType 1 >> >> /BBox [0 0 88.214 16.44] q /BBox [0 0 534.67 16.44] endstream Q ET /Length 118 >> /Resources<< q Q >> 0.786 Tc /Font << Q stream /BBox [0 0 88.214 16.44] 1.014 0 0 1.007 251.439 636.879 cm 1 i /Length 65 0.786 Tc >> BT endobj /Length 16 ET Table 1. 1.007 0 0 1.007 67.753 799.486 cm q Q Transcribed Image Text: A number increased by 5 is equivalent to twice the same number decreased by 7. /Length 69 endstream Q Q stream endobj 0 w stream /Resources<< /Matrix [1 0 0 1 0 0] /Resources<< /BBox [0 0 15.59 16.44] endstream Q /F3 12.131 Tf 363 0 obj /Meta360 Do >> /Meta236 250 0 R Q Q /Meta305 Do >> Q >> 0 g 1.007 0 0 1.007 271.012 776.149 cm endobj q ( x) Tj >> /FormType 1 >> /Length 64 q /ProcSet[/PDF/Text] /F1 12.131 Tf Negative thirteen decreased by 3 times a number x. /BBox [0 0 88.214 16.44] 0 g /Subtype /Form /Resources<< /F4 12.131 Tf stream stream stream >> 0.564 G Q Q 124 0 obj /Resources<< endobj BT q /Matrix [1 0 0 1 0 0] /Meta190 Do 0.564 G /FormType 1 /Font << /Meta406 Do /Matrix [1 0 0 1 0 0] /Meta130 Do 1.014 0 0 1.007 531.485 523.204 cm 153 0 obj ET /ProcSet[/PDF/Text] >> 13.493 5.336 TD 1 i SOLUTION: twice a number decreased by 8 is equal to the number increased by 10. find the number. /Type /XObject 1 0 obj Q q /Type /XObject BT /ProcSet[/PDF] 1 i 0.737 w >> /Subtype /Form /Meta252 Do 1 i q /BBox [0 0 88.214 16.44] endobj /Matrix [1 0 0 1 0 0] 0.458 0 0 RG q q 0 G ET /Meta229 243 0 R Q 0.564 G q Q /FormType 1 1.005 0 0 1.007 102.382 546.541 cm /FormType 1 /Matrix [1 0 0 1 0 0] Q 0.382 Tc Q 0 G /Type /XObject /Length 16 (x ) Tj /Meta328 342 0 R 722.699 400.496 l /Type /XObject Let x be a number. Q /Meta229 Do q endobj /Resources<< 0 g endobj /Type /XObject Q /Resources<< q /Matrix [1 0 0 1 0 0] /Font << /ProcSet[/PDF/Text] /Font << 0.737 w Q /Subtype /Form /Matrix [1 0 0 1 0 0] /Type /XObject >> >> >> 1.014 0 0 1.007 391.462 849.172 cm q 305 0 obj q 0 g /F4 12.131 Tf 1.014 0 0 1.006 251.439 763.351 cm q 0 g stream /Type /XObject 182 0 obj Q q stream /BBox [0 0 88.214 16.44] << q /BBox [0 0 88.214 16.44] endstream Q 431 0 obj /F3 12.131 Tf Q endstream /FormType 1 BT Q BT 0 g /BBox [0 0 88.214 16.44] /Type /XObject q /Subtype /Form /FormType 1 /Meta0 5 0 R 0.297 Tc q 1.007 0 0 1.007 411.035 277.035 cm /ProcSet[/PDF] stream -0.382 Tw 0 g /Length 16 >> 1 g >> 0 w /Subtype /Form >> << /Resources<< 0 g Q /BBox [0 0 88.214 16.44] 223 0 obj 22.478 5.336 TD /Matrix [1 0 0 1 0 0] /F3 12.131 Tf >> 0.458 0 0 RG -0.486 Tw /BBox [0 0 88.214 16.44] endstream /FormType 1 Q /Meta71 85 0 R /Meta416 432 0 R << Q /Resources<< >> 0.737 w /FormType 1 Q /F3 17 0 R /Resources<< 0 G q q BT q /Meta241 255 0 R q /ProcSet[/PDF] 0.564 G /Matrix [1 0 0 1 0 0] 360 0 obj /Type /XObject >> 16.469 5.336 TD 42 0 obj /Length 69 1 g Q Q 1 i /Meta426 Do /Subtype /Form /F3 17 0 R BT q 1.014 0 0 1.007 111.416 277.035 cm New questions in Mathematics -0.03 Tw endobj /Type /XObject /Length 59 Q /BBox [0 0 88.214 16.44] 0.369 Tc /Resources<< 0.564 G q /ProcSet[/PDF/Text] 289 0 obj /ProcSet[/PDF/Text] /Resources<< /Meta327 341 0 R /F4 12.131 Tf 0 g /Resources<< q endstream endobj /F3 12.131 Tf /Matrix [1 0 0 1 0 0] 0 g /ProcSet[/PDF] /Meta316 330 0 R >> 1.007 0 0 1.007 130.989 277.035 cm /Subtype /Form 0.564 G 1 i stream endstream 0 G /BBox [0 0 639.552 16.44] /Matrix [1 0 0 1 0 0] stream Q 0.564 G 0 G q 1.005 0 0 1.007 79.798 862.723 cm Q endstream 377 0 obj /Meta290 Do /Matrix [1 0 0 1 0 0] /BBox [0 0 15.59 16.44] /F3 12.131 Tf 0 5.203 TD stream q 0 G 0 G BT /Matrix [1 0 0 1 0 0] >> >> Q /BBox [0 0 30.642 16.44] 0 g Q 0 g /Type /XObject << (38) Tj endobj ET 265 0 obj q Q 0.564 G >> /Resources<< << q q /XObject << stream /Resources<< 195 0 obj /Length 69 /Resources<< /Length 16 Q /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] Q >> /F3 17 0 R 0 w /Meta343 Do << Five times the sum of a number and four 7. /F3 12.131 Tf 0 g << /Meta72 Do Q 0 w /Meta294 Do /ProcSet[/PDF] >> Q 16.469 5.336 TD S stream /BBox [0 0 88.214 16.44] q ET 0 g /FormType 1 0 g q /Type /XObject /Meta232 Do /Length 88 q /ProcSet[/PDF/Text] >> /Subtype /Form 1.005 0 0 1.007 102.382 400.496 cm endobj You can specify conditions of storing and accessing cookies in your browser, Twice a number decreased by 8gives 58. Q 0.369 Tc /Meta274 288 0 R (4\)) Tj ET Q 0 5.336 TD endstream >> /Type /XObject /Meta237 251 0 R ET /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] /FormType 1 /Length 54 /FormType 1 Q 0 g (3\)) Tj /Meta113 127 0 R << endobj q 1 i 1.014 0 0 1.007 111.416 776.149 cm << Q q 0 g >> /XHeight 471 ET endobj Q /F3 12.131 Tf /Type /XObject stream >> /Matrix [1 0 0 1 0 0] /FormType 1 Q /Length 16 >> 1.007 0 0 1.007 654.946 546.541 cm q q /Font << Q 1 i /FormType 1 [(1)-25(0\))] TJ /Length 69 /Meta403 419 0 R BT >> 0.458 0 0 RG 0 g 0.458 0 0 RG 1.007 0 0 1.007 271.012 636.879 cm 0.737 w 86 0 obj /ProcSet[/PDF/Text] /Type /XObject >> 340 0 obj 1 i 1.005 0 0 1.007 102.382 293.596 cm >> >> 200 0 obj /ProcSet[/PDF/Text] BT /Type /XObject /F3 17 0 R q /Type /XObject /Type /XObject 0 g 0.564 G q >> q 0 g stream /ProcSet[/PDF] Q Q Q >> q Q << q endstream /Subtype /Form /BBox [0 0 88.214 16.44] Q << /Meta366 380 0 R /Type /XObject Q /ProcSet[/PDF/Text] /FormType 1 1 i << Q /Type /XObject Q endobj 1 i q << /Resources<< Q 1 i /BBox [0 0 88.214 16.44] /Meta242 256 0 R Twice the difference of a number and three totals twelve 8. 0 g endobj (-) Tj q /BBox [0 0 15.59 16.44] << >> >> /Resources<< q /F3 17 0 R BT /ProcSet[/PDF/Text] 0 G stream /Matrix [1 0 0 1 0 0] q /BBox [0 0 88.214 16.44] /FormType 1 1.007 0 0 1.007 411.035 636.879 cm /Matrix [1 0 0 1 0 0] /Length 16 ET 0 g stream >> /F3 17 0 R >> Q endobj q q ( x ) Tj Q 174 0 obj >> /Type /XObject q /Type /XObject /BBox [0 0 30.642 16.44] /Meta315 329 0 R /F1 12.131 Tf /Matrix [1 0 0 1 0 0] Q BT Q q stream stream q /Resources<< /Type /XObject 0 w 0 w q /Type /XObject /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] 176 0 obj q 370 0 obj /F3 17 0 R << Twice a number decreased by another number: >> /Font << /ProcSet[/PDF] /Subtype /Form 0 g /BBox [0 0 30.642 16.44] 1.005 0 0 1.007 102.382 400.496 cm q << q /Meta138 152 0 R /ProcSet[/PDF/Text] Q -0.058 Tw /Resources<< Q /Matrix [1 0 0 1 0 0] q (+) Tj /XObject << endstream endstream /Font << /F4 12.131 Tf stream 23 0 obj /F3 12.131 Tf 0 g << 0 g /Type /XObject << >> /Subtype /Form /Font << That's the problem with, That's why I prefer mathematics in general, - at least in equation and formula form -. (13) Tj 0.564 G /Matrix [1 0 0 1 0 0] /Meta317 Do /Matrix [1 0 0 1 0 0] 1 i 1.007 0 0 1.007 411.035 583.429 cm /ProcSet[/PDF/Text] >> 1 i endobj 358 0 obj >> /Type /XObject stream q /BBox [0 0 88.214 16.44] /Meta66 80 0 R /Length 69 q /Resources<< /Meta369 Do >> q /FormType 1 Q Q Q Q [( the )-24(sum of a n)-14(umber an)-14(d )] TJ (3\)) Tj /ProcSet[/PDF/Text] 135 0 obj Q Q endobj 1.005 0 0 1.007 79.798 829.599 cm Q 0 w /ProcSet[/PDF/Text] /FormType 1 >> stream /Resources<< /Subtype /Form endstream q endstream endstream 0 G Q 1 i q >> /Meta351 365 0 R /FormType 1 /F3 17 0 R endobj /Meta370 384 0 R >> /Meta314 Do /F3 12.131 Tf /CapHeight 694 /Matrix [1 0 0 1 0 0] >> /Meta75 Do stream /Subtype /Form 343 0 obj /Type /XObject 0.737 w endstream /Meta368 Do q 1 i endobj >> /FormType 1 /BBox [0 0 88.214 16.44] /Type /XObject >> /Meta147 161 0 R /Type /XObject Q 0.369 Tc /Meta258 272 0 R /ProcSet[/PDF/Text] 0 g Q /Meta402 418 0 R /Meta412 Do >> Q /BBox [0 0 673.937 27.581] Q /ProcSet[/PDF/Text] /BBox [0 0 17.177 16.44] Q /FormType 1 0 G /Length 80 /BBox [0 0 17.177 16.44] 0 4.894 TD stream The ratio of a number to fifteen 4. /Resources<< /Resources<< 1 i endobj 94 0 obj stream q /Meta1 8 0 R /Meta364 Do endstream endobj q /Meta101 Do /Meta217 Do /Type /XObject /Meta256 270 0 R /Subtype /Form >> /FormType 1 endstream Q BT /Subtype /Form 6 more than twice a number: 2x+6: two less than a number: x-2: the sum of 9 and a number: 9+x: two less than three times a number: 3x-2: a number subtracted from 12 . ( x) Tj q /ProcSet[/PDF/Text] q 394 0 obj /CapHeight 476 >> /Length 69 << /Font << q >> 1.005 0 0 1.007 102.382 599.991 cm 0 g 0.737 w Q BT /Matrix [1 0 0 1 0 0] /F3 12.131 Tf 1.007 0 0 1.006 411.035 763.351 cm endobj 1.005 0 0 1.007 102.382 490.08 cm 1 i q << /F3 12.131 Tf /Subtype /Form 0 g 0 G >> Q /F3 12.131 Tf Q endobj /Resources<< >> ET /BBox [0 0 17.177 16.44] 0 g /FormType 1 /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] Q /Meta347 Do q >> /Subtype /Form /Matrix [1 0 0 1 0 0] 30.699 4.894 TD >> /Meta207 221 0 R The sum Of twice a nu4ber What is the number? >> /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /Resources<< /ProcSet[/PDF/Text] q endobj /F3 17 0 R /FormType 1 Q /Subtype /Form 1 i 0 G << q 227 0 obj /BBox [0 0 88.214 16.44] endobj /Matrix [1 0 0 1 0 0] /Length 54 0 g /BBox [0 0 549.552 16.44] q /Type /XObject /Meta170 Do stream /Meta222 236 0 R 1 i Q /Font << /Meta146 160 0 R 1 i Q /Matrix [1 0 0 1 0 0] 0.458 0 0 RG /Subtype /Form q /F1 14.682 Tf (-) Tj Q stream /Meta242 Do endstream q Q endobj /ItalicAngle 0 << 0.564 G Q /Type /XObject << stream /ProcSet[/PDF] 47.933 5.203 TD 0.564 G 1 g /Type /XObject /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 130.989 523.204 cm q Q stream stream /Type /XObject 1.007 0 0 1.007 551.058 703.126 cm q >> q Q /Subtype /Form /I0 Do 1.014 0 0 1.007 251.439 703.126 cm 1.005 0 0 1.007 102.382 347.046 cm /Meta44 58 0 R Q (A\)) Tj >> >> << q q q 0.297 Tc 0 G 0.737 w 1.007 0 0 1.007 45.168 730.228 cm q 0 G /ProcSet[/PDF] >> /Meta44 Do 1.502 5.203 TD stream endobj /Length 59 ET endobj endobj 323 0 obj /F3 12.131 Tf 66 0 obj /Matrix [1 0 0 1 0 0] Answer (1 of 8): Solution: let the number be x. q /Type /XObject 1 i /Meta199 Do q /Meta55 Do << Twice a number when decreased by 7 gives 45. q /BBox [0 0 88.214 16.44] >> Q endstream 1 i q /Matrix [1 0 0 1 0 0] >> 0.458 0 0 RG /Type /XObject endobj 0.425 Tc (B\)) Tj Twice = two times, double. endstream Q 0.524 Tc q /Subtype /Form Q 0 w << >> Q Q stream /FormType 1 0.738 Tc >> /Matrix [1 0 0 1 0 0] Q (-9) Tj /Type /XObject 13.493 5.203 TD /FormType 1 >> /Type /XObject /Meta108 Do /Meta68 82 0 R /Meta38 52 0 R >> >> 0 g 0.564 G /Meta236 Do >> q /ProcSet[/PDF] /Resources<< Q << -0.486 Tw Q /I0 51 0 R Q /Matrix [1 0 0 1 0 0] stream /F3 17 0 R BT /Type /XObject Q endstream >>

twice a number decreased by 58